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CGP EDU Academic Team
Published on: August 21, 2026
3O 2 (g) 
2O 3 (g)
for the above reaction at 298 K, K c is found to be 3.0 x 10 -59 . If the concentration of O 2 at equilibrium is 0.040 M then concentration of O 3 in M is
Text Solution
Verified by ExpertsThe correct answer is:
3O 2 (g) 
2O 3 (g)
[O 3 ] 2 =K C [O 2 ] 3 = 3 x 10 -59 x (0.04) 3
[O 3 ] 2 = 1.9 x 10 -63 = 19 x 10 -64
[O 3 ]=4.38 x 10 -32
Therefore, concentration of O 3 at equilibrium = 4.38 x 10 -32 M
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